Question

evaluate a^-2b^0 for a =3 and b=4

Answer 1

If you mean: (a^-2)(b^0), then you get:

(3^-2)(4^0)=[(1/3)^2][1]=1/9

Answer 2

\[3^{-2} 4^0\]
\[3^{-2}\times 1\]

Answer 3

\[3^{-2}=\frac{1}{3}^2=\frac{1}{9}\]