Question

how many places will the graph y = x^2-6x+6 intersect the axis?

Answer 1

two

Answer 2

so how did you get that?

Answer 3

putting y=0
x^2-6x+6=0
so\[x=\frac{6\pm \sqrt{6^2-24}}{2}\]

Answer 4

no the ans is not (x-3)(x-3)=0
just check within the radical i have 6^2-24=12 so x=3+-sqrt(3)

Answer 5

yes dipank you are right - i had a mental block there - thats why i deleted the reply lol