Question

lim as x=>3- ((sqrtx^2+16)-5)/(x^2-9)

Answer 1

\[\lim_{x \rightarrow 3-}\] \[{\sqrt{x^2+16}-5}/{\sqrt{x^2-9}}\]

Answer 2

\[x\rightarrow 3-\,\Rightarrow\sqrt{x^2-9}\,\notin\,\mathbb{R}\]

Answer 3

right.

Answer 4

then, limit does not exist

Answer 5

there's no way to factor out the discontinuity?