Question

how do you solve 3x^2+40=-x^2-56

Answer 1

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Answer 2

3x^2+40= -x^2-56
3x^2 +x^2 = -56-40
4x^2 =-96
x^2 = -96/4
x^2 = -24
x=sq. root of -24
x =2sq.root of -6

Answer 3

x= 2i sq.root of 6
where i = sq root of -1