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Mathematics 20 Online
OpenStudy (anonymous):

differentiate y'=y y(2)=3

OpenStudy (anonymous):

ke^x

OpenStudy (anonymous):

okay...

OpenStudy (anonymous):

ke^2=3

OpenStudy (anonymous):

okay...

OpenStudy (anonymous):

k=3/(e^2) y=\[y={3 \over e^2}e^x\]

OpenStudy (anonymous):

Okay...thank you!

OpenStudy (anonymous):

I have one more differentiating equation if you want to answer.

OpenStudy (anonymous):

sure

OpenStudy (anonymous):

it's going to be a new question so you can answer it

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