Question

Let the function f be defined by y = f(x), where x and f(x) are real numbers.

Find the following. (Simplify your answers completely.) f(x)=3/7x+5
f(2) =
f(−3) =
f(k) =
f(k2 − 1) =

Answer 1

f(2) = 3/7(2)+5
=3/14+5
=73/14


similarly
f(-3) = 3/7(-3)+5
=3/-21 +5
=-102/-21
=102/21

f(k) = (3+35k)/7

f(k\(^{2}\)) = (3+35k\(^{2}\))/7

Answer 2

is this \[f(x)=\frac{3}{7x+5}\]

Answer 3

if so then
\[f(2)=\frac{3}{7\times 2+5}=\frac{3}{19}\]

Answer 4

and likewise
\[f(-3)=\frac{3}{7\times -3+5}=-\frac{3}{16}\]\]