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Mathematics 17 Online
OpenStudy (anonymous):

factor completly: 10y^5 - 32y^4 + 6y^3

OpenStudy (anonymous):

Start by factoring out a 2y^3 giving: \[2y^3(5y^2-16y+3)\] From here, factor the rest giving. \[2y^3(5y-1)(y-3)\]

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