Question

Solve the following system of equations alebraically:

2x+3y=17
3x-2y=-0.5

x=
y=

Answer 1

ok well first u need to find one variable so u do
2x+3y=17
2x=(-3y+17)/2
x=-3/2 y +17/2
3x-2y=-.5
now u substitue so
3(-3/2 y + 17/2) -2y=-.5
-4.5+25.5-2y=-.5
21-2y=-.5
-2y=20.5
y=10.25

Answer 2

now you got y, you can find x
so 2x+3y=17
2x+3(10.25)=17
2x+30.75)=17
2x=-13.25
x=-6.625