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OpenStudy (owlfred):
Hoot! You just asked your first question! Hang tight while I find people to answer it for you. You can thank people who give you good answers by clicking the 'Good Answer' button on the right!
OpenStudy (anonymous):
Yes
myininaya (myininaya):
a polynomial is of the form
P(x)=a0+a1x+a2x^2+a3x^3+....+anx^n
where n is an integer greater than zero
OpenStudy (anonymous):
i dont get some of these they are confusing me
OpenStudy (anonymous):
myininaya i have no idea wha you are talking about
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myininaya (myininaya):
greater than or equal to zero
OpenStudy (anonymous):
ok il give you a prob
OpenStudy (anonymous):
x^2 +6x +9
factor each trinomial into a product of 2 binomials
myininaya (myininaya):
\[P(x)=a_0+a_1x+a_2x^2+a_3x^3+....+a_nx^n\]
is that better?
OpenStudy (anonymous):
(x+3)(x+3)
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OpenStudy (anonymous):
no im in algebra 1 i have know idea what you are saying sorry?!
OpenStudy (anonymous):
When you are factoring a polynomial look for first and last term
OpenStudy (anonymous):
imranmeah91 how do you get that
myininaya (myininaya):
all the a ares just constants
OpenStudy (anonymous):
ok
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myininaya (myininaya):
just find 2 factors of 9 that add up to be 6
myininaya (myininaya):
and put those numbers in the following blanks
(x+__)(x+__)
OpenStudy (anonymous):
In your case you have x^2+6x+9
what two number should you multiply to get 9 --- 3 & 3
x^2 ---- x & x
(x+3)(x+3)
OpenStudy (anonymous):
kk
myininaya (myininaya):
so if we have
x^2+5x+6
what two factors of 6 add up to be five then put them in the blanks below
(x+__)(x+__)
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OpenStudy (anonymous):
3+3
OpenStudy (anonymous):
if your polynomial is just positive like this
__+___+__
your factor will be
( + )( + )
If it is
___ -____+_____
( - )( - )
OpenStudy (anonymous):
ok
myininaya (myininaya):
what are factors of 6:
1(6)=6
2(3)=6
does any of these products have factors that add up to be 5?
OpenStudy (anonymous):
____+_____-_____
( + )( - )
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OpenStudy (anonymous):
i think i get it now thanks
OpenStudy (anonymous):
3*2=6
3+2=5
myininaya (myininaya):
right so
x^2+5x+6=(x+3)(x+2)
OpenStudy (anonymous):
what about x^2 + 8x +7
OpenStudy (anonymous):
what is factor of 7
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myininaya (myininaya):
what are two factors of 7 that multiply to be 7 and and add up to be 8?
OpenStudy (anonymous):
1 and 7?
OpenStudy (anonymous):
that's it
myininaya (myininaya):
lol yes
that is the only factors of 7 gj not alot of thinking for that one rihgt?
myininaya (myininaya):
well there is also -1 and -7 but we don't need them since the middle term is positive
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OpenStudy (anonymous):
so would it be (x+7) (x+1)
OpenStudy (anonymous):
Yes
myininaya (myininaya):
yes!
what is
the factors for x^2-8x+7
OpenStudy (anonymous):
use my rules above
OpenStudy (anonymous):
i willl
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OpenStudy (anonymous):
what about
x^2 - x - 12
and x^2 - 25
OpenStudy (anonymous):
My rule
__-___-___
would be
( - )( + )
(x - ) ( x + )
Factor of 12 , that have -1