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Mathematics 7 Online
OpenStudy (anonymous):

anyone know about polynomials?

OpenStudy (owlfred):

Hoot! You just asked your first question! Hang tight while I find people to answer it for you. You can thank people who give you good answers by clicking the 'Good Answer' button on the right!

OpenStudy (anonymous):

Yes

myininaya (myininaya):

a polynomial is of the form P(x)=a0+a1x+a2x^2+a3x^3+....+anx^n where n is an integer greater than zero

OpenStudy (anonymous):

i dont get some of these they are confusing me

OpenStudy (anonymous):

myininaya i have no idea wha you are talking about

myininaya (myininaya):

greater than or equal to zero

OpenStudy (anonymous):

ok il give you a prob

OpenStudy (anonymous):

x^2 +6x +9 factor each trinomial into a product of 2 binomials

myininaya (myininaya):

\[P(x)=a_0+a_1x+a_2x^2+a_3x^3+....+a_nx^n\] is that better?

OpenStudy (anonymous):

(x+3)(x+3)

OpenStudy (anonymous):

no im in algebra 1 i have know idea what you are saying sorry?!

OpenStudy (anonymous):

When you are factoring a polynomial look for first and last term

OpenStudy (anonymous):

imranmeah91 how do you get that

myininaya (myininaya):

all the a ares just constants

OpenStudy (anonymous):

ok

myininaya (myininaya):

just find 2 factors of 9 that add up to be 6

myininaya (myininaya):

and put those numbers in the following blanks (x+__)(x+__)

OpenStudy (anonymous):

In your case you have x^2+6x+9 what two number should you multiply to get 9 --- 3 & 3 x^2 ---- x & x (x+3)(x+3)

OpenStudy (anonymous):

kk

myininaya (myininaya):

so if we have x^2+5x+6 what two factors of 6 add up to be five then put them in the blanks below (x+__)(x+__)

OpenStudy (anonymous):

3+3

OpenStudy (anonymous):

if your polynomial is just positive like this __+___+__ your factor will be ( + )( + ) If it is ___ -____+_____ ( - )( - )

OpenStudy (anonymous):

ok

myininaya (myininaya):

what are factors of 6: 1(6)=6 2(3)=6 does any of these products have factors that add up to be 5?

OpenStudy (anonymous):

____+_____-_____ ( + )( - )

OpenStudy (anonymous):

i think i get it now thanks

OpenStudy (anonymous):

3*2=6 3+2=5

myininaya (myininaya):

right so x^2+5x+6=(x+3)(x+2)

OpenStudy (anonymous):

what about x^2 + 8x +7

OpenStudy (anonymous):

what is factor of 7

myininaya (myininaya):

what are two factors of 7 that multiply to be 7 and and add up to be 8?

OpenStudy (anonymous):

1 and 7?

OpenStudy (anonymous):

that's it

myininaya (myininaya):

lol yes that is the only factors of 7 gj not alot of thinking for that one rihgt?

myininaya (myininaya):

well there is also -1 and -7 but we don't need them since the middle term is positive

OpenStudy (anonymous):

so would it be (x+7) (x+1)

OpenStudy (anonymous):

Yes

myininaya (myininaya):

yes! what is the factors for x^2-8x+7

OpenStudy (anonymous):

use my rules above

OpenStudy (anonymous):

i willl

OpenStudy (anonymous):

what about x^2 - x - 12 and x^2 - 25

OpenStudy (anonymous):

My rule __-___-___ would be ( - )( + ) (x - ) ( x + ) Factor of 12 , that have -1

OpenStudy (anonymous):

but how do yo get the single x

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