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F(x)=x2+8x+7 find the vertex.
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-b/2a
what imran said. in this case b= 8, a = 1 \[\frac{-b}{2a}=-\frac{8}{2}=-4\]
then plug in -4 for x to get \[f(-4)=(-4)^2+8\times -4=16-32+7=-16+7=-9\]
so vertex is (-4,-9)
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