Question

I need help. x^2+4x-32=0

Answer 1

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Answer 2

factor as \[xZ^2+4x-32=(x-4)(x+8)\]
\[(x+4)(x-8)=0\]
\[x+4=0\]
\[x=-4\]
\[x-8=0\]
\[x=8\]

Answer 3

thaks