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simplifyy 9y^2-1/2y-1 X[multiply] 1-2y/3y-1
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\[\frac{9x^2-1}{2y-1}\times \frac{1-2y}{3y-1}\]
\[\frac{(3y-1)(3y+1)}{2y-1}\times \frac{1-2y}{3y-1}\]
3y-1 cancels top and bottom and \[\frac{1-2y}{2y-1}=-1\] so it cancels as well
leaving nothing but \[-(3y+1)=-3y-1\]
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so that means y is 1 ?
thanks a lot
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