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What is Laplace transform of f(t)=10sin(2t-30degrees) ?
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Using the table or without the table?
Using the table, we get (10(2t + 30))/(s^2 + (2t+30)^2)
The laplace for sinbt = b/(s^2 + b^2)
O.K. Than you!!
WOOPS. I just noticed I used 2t+30 instead of 2t-30. Just replaacee everywhere i've put 2t+30 with 2t-30
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O.K. I got it.Thank you !!
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