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OpenStudy (anonymous):
7^(4x+1)=5
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OpenStudy (anonymous):
try taking log on both sides
OpenStudy (anonymous):
\[7^{(4x+1)}=5\]\[(4x+1)\ln 7=\ln 5\]\[4x+1=\frac{\ln 5}{\ln 7}\]x=\[x=\frac{1}{4}(\frac{\ln5}{\ln7}-1)\]
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