An ordinary (fair) die is a cube with the numbers through on the sides (represented by painted spots). Imagine that such a die is rolled twice in succession and that the face values of the two rolls are added together. This sum is recorded as the outcome of a single trial of a random experiment.

Compute the probability of each of the following events:

Event : The sum is greater than 5 .
Event : The sum is divisible by 5.

Question

An ordinary (fair) die is a cube with the numbers  through  on the sides (represented by painted spots). Imagine that such a die is rolled twice in succession and that the face values of the two rolls are added together. This sum is recorded as the outcome of a single trial of a random experiment.

Compute the probability of each of the following events:

Event : The sum is greater than 5 .
Event : The sum is divisible by 5.

anonymous · Answer

Total possible outcomes are 36
Out of these 26 will give sum greater than 5

so P(sum greater than 5) = 26/36 = 13/18

anonymous · Answer

For 7 outcomes the sum is divisible by 5

So P(sum is divisible by 5) = 7/36


Hope it is clear.....???