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Mathematics 16 Online
OpenStudy (anonymous):

what is the answer of it (wait ill write it to bottom..

OpenStudy (anonymous):

\[\int\limits_{-1}^{1}2x^{2}*dx\] i found the answer as 4/3 am i right or not?

OpenStudy (anonymous):

are you writing a noval?

OpenStudy (angela210793):

\[=\int\limits_{-1}^{1} 2x^2dx=2\int\limits_{-1}^{1}x^2dx=[2x^3/3]\]

OpenStudy (angela210793):

haha no :P

OpenStudy (angela210793):

2x^3/3 sorry

OpenStudy (anonymous):

no look carefull give r = 1and then give r = -1 then do !!

OpenStudy (angela210793):

w8 i haven't finished yet

OpenStudy (anonymous):

you see? it will be 2.1 / 3 - (-2/3) and now !!

OpenStudy (angela210793):

2/3-(-2/3)=2/3+2/3=4/3

OpenStudy (anonymous):

then it will be 4/3 ^^

OpenStudy (angela210793):

and ur right!!! Good job :)

OpenStudy (anonymous):

:) yes !! fianlly integral xd

OpenStudy (angela210793):

Yupii!!!! :P:)

OpenStudy (anonymous):

well Ill be better then you after 2 mounths on Maths ^^

OpenStudy (angela210793):

we? Who we?

OpenStudy (anonymous):

nono well, I'll be better then you after 2 moutnhs on Maths, but now u are better ^^

OpenStudy (angela210793):

Hahahaha :P:P:P:P Ok :P:P

OpenStudy (anonymous):

omg my gf fulled the exam lol...

OpenStudy (angela210793):

fulled? or failed?

OpenStudy (anonymous):

fulled ^^ she did no mistake

OpenStudy (angela210793):

Oh....gr88 :):):)

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