Mathematics
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OpenStudy (anonymous):
what is the answer of it (wait ill write it to bottom..
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OpenStudy (anonymous):
\[\int\limits_{-1}^{1}2x^{2}*dx\] i found the answer as 4/3 am i right or not?
OpenStudy (anonymous):
are you writing a noval?
OpenStudy (angela210793):
\[=\int\limits_{-1}^{1} 2x^2dx=2\int\limits_{-1}^{1}x^2dx=[2x^3/3]\]
OpenStudy (angela210793):
haha no :P
OpenStudy (angela210793):
2x^3/3 sorry
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OpenStudy (anonymous):
no look carefull
give r = 1and then give r = -1
then do !!
OpenStudy (angela210793):
w8 i haven't finished yet
OpenStudy (anonymous):
you see? it will be 2.1 / 3 - (-2/3) and now !!
OpenStudy (angela210793):
2/3-(-2/3)=2/3+2/3=4/3
OpenStudy (anonymous):
then it will be 4/3 ^^
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OpenStudy (angela210793):
and ur right!!! Good job :)
OpenStudy (anonymous):
:) yes !! fianlly integral xd
OpenStudy (angela210793):
Yupii!!!! :P:)
OpenStudy (anonymous):
well Ill be better then you after 2 mounths on Maths ^^
OpenStudy (angela210793):
we? Who we?
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OpenStudy (anonymous):
nono well, I'll be better then you after 2 moutnhs on Maths, but now u are better ^^
OpenStudy (angela210793):
Hahahaha :P:P:P:P Ok :P:P
OpenStudy (anonymous):
omg my gf fulled the exam lol...
OpenStudy (angela210793):
fulled? or failed?
OpenStudy (anonymous):
fulled ^^ she did no mistake
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OpenStudy (angela210793):
Oh....gr88 :):):)