Find the x-intercept(s) and the coordinates of the vertex for the parabola y = x^2 - 2x - 24 . If there is more than one x-intercept, separate them with commas.

Question

Find the x-intercept(s) and the coordinates of the vertex for the parabola y = x^2 - 2x - 24  . If there is more than one x-intercept, separate them with commas.

anonymous · Answer

x intercepts are -4 and 6

anonymous · Answer

factor and you will get them

amistre64 · Answer

i like completeing the square for these; its quicker

24 = x^2 -2x

24+1 = x^2 -2x+1

25 = (x-1)^2

+- 5 = x-1

x = 1+5; 1-5

x = 6,-4

amistre64 · Answer

well; its more effortless then trial and error I should say lol

anonymous · Answer

wait so if those r the x-intercepts whic is the vertex ?

anonymous · Answer

vertex use 
$$-\frac{b}{2a}$$

amistre64 · Answer

vertex should be 1,-25 if i see it right

anonymous · Answer

this does not ask for vertex.

amistre64 · Answer

"Find the x-intercept(s) and the coordinates of the vertex ..."

anonymous · Answer

half way between -4 and 6 is 1 yes

amistre64 · Answer

those 2 part questions will bite you every time lol

anonymous · Answer

i 4 got 2 include it in the question its lokking for the x-intecept(s) and the vertex.....sorry

anonymous · Answer

and if x = 1 y = -25

anonymous · Answer

so the vertex is (1,-25) ?

anonymous · Answer

so intercepts are (-4,0) and (6,0)
vertex is (1,-25)

anonymous · Answer

THANK YOU !!!!!!!!!!!!!!!!!!!!!!!