a speedboat traveled 2 hours with a 4km/h current before turning around. the return trip against the same current took 3 hours. find the speed of the boat in still water

Question

amistre64 · Answer

s = d/t  is usually used to aid in this word problem

anonymous · Answer

ok im just trying to figure if i got it right after solving it wat did u get

amistre64 · Answer

total speed = boatspeed + currentspeed ; STILL WORKING ON IT LOL

anonymous · Answer

2(x+4)=3(x-4)

amistre64 · Answer

they really should move the caps lock key to a new place

anonymous · Answer

its cool take ur time u r the one helping me lol i kno right

amistre64 · Answer

imran; has a good setup

anonymous · Answer

speed in still water is 20

anonymous · Answer

yeah its just i never get past that part i mean i kno it easy but........

anonymous · Answer

ty

anonymous · Answer

welcome

amistre64 · Answer

think of it as:

distance = distance

time(speed) = time(speed)

anonymous · Answer

well put amistre

anonymous · Answer

ok easier ty

amistre64 · Answer

2(boat speed + current) = 3(boat speed - current)