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Factor out polynomial 2x^2-3x-3
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i get what this is. it's just for me little confusing how to do this.
this cannot be factorized
it's prime
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x={-0.8228756555, 1.8228756555} these are the answer but i don't know how to do it step by step.
\[(-b \pm \sqrt{b ^{2}-4ac})/2a=x\] where a is coefficient of x^2, b is coefficient of x, c is the constant. http://gcse.wikia.com/wiki/Quadratic_formula the square root gives you 2 answers
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