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X^2-2x=80?????
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rearranging u get x^2 - 2x -80 = 0 Find the roots of this quadratic equation If u need more help with this, say so
Using the "Splitting the middle term", it can be written as x^2 -10 x + 8x - 80 = 0 x(x - 10) +8(x - 10) = 0 (x -10) (x+8) = 0 This is possible if either (x - 10) is zero or (x + 8) is zero If x - 10 = 0 means x = 10 If x + 8 = 0 means x = -8
Hence the two values of x are 10 and -8
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