Question

write an equation for the parabola whose vertex is at (3,3) and passes through (5,27)

Answer 1

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Answer 2

y = a(x-h)^2 +k
vertex: (h,k) = (3,3)
y=a(x-3)^2 +3
use (5,27) for x and y, solve for a
27 = a(5-3)^2 +3
27 = 4a +3
24 = 4a
6 = a

y = 6(x-3)^2 + 3

Answer 3

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