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x^4-17x^2+16=0 has how many positive and negative real zeroes?
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(x^2-16)(x^2-1)=0 x^2=16,1 x=+-4.+-1
two _ve real zero and 2 negative
u can replace x^2 with a t and u'll have t^2-17t+16=0 and u can solve it as a second grade eq.
Angela knows her stuff.
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