Question

T(n)=1/(1-3n) would be expanded as 1+3n+3^2n^2+..........+3^rn^r....... how it is possible???

Answer 1

1/(1-3n)=(1-3n)^-1 =1+(-1)(-3n)+(-1)^2(3n)^2+(-1)^3(-3n)^3+......+(-1)^r(-3n)^r+....

=1+3n+3^2n^2+......3^rn^r+......
this is the binomial theorem...do u know that?

Answer 2

thanks......