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A man has some hens & some cows. If the number of heads is 50 & number of feet is 42. The number of cows is ?
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sorry feest are 142 !!
feets-142
It's almost 21 hens, remaining are cows
maybe 11 cows
a cow has 4 feet and a hen 2 x=no of a cow's feet y=no of a hen's feet ---> we can form a system 4x+2y=149 (1) x+y=50 (2) Tht's wht i think....and i guess u know how to solve this system
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x=cow and y=hen
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