Question

find the vertex of the quadratic function:
f(x)=3x^(2)-12x=16

Answer 1

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Answer 2

2,4

Answer 3

to find the vertex either "complete the square" or just use
\[x=-\frac{b}{2a}\]

in this case b = -12, a = 3 so
\[-\frac{b}{2a}=-\frac{-12}{2\times 3} = 2\] to get the y value find
\[f(2)=3\times 2^2-12\times 2 -16=12-24-16=-28\]

Answer 4

btw i am assuming this is
\[f(x)=3x^2-12x-16\] not
\[f(x)=3x^2-12x=16\] which doesn't make any sense