how do you solve 2l3x-1l=22 (Solve for x)
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divide by 2 and then solve two separate equations
\[2|x=3x-1|=22\] \[|3x-1|=11\] \[3x-1=11\] or \[3x-1=-11\]
typo on the first line should just say \[2|3x-1|=22\]
both equation easy to solve \[3x-1=11\] \[3x=12\] \[x=4\] or \[3x-1=-11\] \[3x=-10\] \[x=-\frac{10}{3}\] and those are the two solution,
ok?
thanks man.
welcome!
\[2|3x-1|=22\] then you subtract the 2 from the 22 after this you now have \[|3x-1|=20\] now you take this and make two solutions one being 3x-1=20 and 3x-1=-20 you solv for x and your two solutions will be (7,-19/3)
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