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OpenStudy (anonymous):
A ship off-shore from a vertical cliff known to be 200 ft high, takes a sighting of the top of a cliff. If the angle of elevation is found to be 15 degrees, approximately how far is the off-shore is the ship?
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OpenStudy (amistre64):
tan(15) = 200/distance d = 200/tan(15)
OpenStudy (amistre64):
d = 746.410...... fts
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