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Mathematics 12 Online
OpenStudy (anonymous):

Q=kor*(0.5)^2*(0.9)^1/2 kor=2.09 Q=2.09*(0.5)^2*(0.9)^1/2 Q=0.49568... Now say if I knew Q was 0.495.. and wanted to find kor, how would I rearrange the formula to get the answer 2.09? 0.4956=kor*(0.5)^2*(0.9)^1/2 Btw the above formula is related to Water Calcs for Orfices if it helps.

OpenStudy (owlfred):

Hoot! You just asked your first question! Hang tight while I find people to answer it for you. You can thank people who give you good answers by clicking the 'Good Answer' button on the right!

OpenStudy (anonymous):

kor=Q/[(0.5)^2*(0.9)^0.5]

OpenStudy (anonymous):

Yeah worked perfectly, having a brain freeze as I have a test in two days and stressing. Thanks alot!

OpenStudy (anonymous):

:)

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