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Mathematics 19 Online
OpenStudy (anonymous):

x^2+1 divided by 3x^5+15x^3+3x^2-5x+3

OpenStudy (amistre64):

its a proper fraction already ..... may be able to factor and simplify tho

OpenStudy (amistre64):

divide the top into the bottom and see if its remainder is 0

OpenStudy (amistre64):

3x^3 +12x +3 --------------------------- x^2+1| 3x^5 +15x^3 +3x^2 -5x +3 -3x^3 --------------------- 12x^3 +3x^2 -5x +3 -12x ------------------ 3x^2 -17x +3 -3 ------------- -17x hmmmm

OpenStudy (anonymous):

thats not correct

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