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OpenStudy (anonymous):
x^2+1 divided by 3x^5+15x^3+3x^2-5x+3
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OpenStudy (amistre64):
its a proper fraction already ..... may be able to factor and simplify tho
OpenStudy (amistre64):
divide the top into the bottom and see if its remainder is 0
OpenStudy (amistre64):
3x^3 +12x +3
---------------------------
x^2+1| 3x^5 +15x^3 +3x^2 -5x +3
-3x^3
---------------------
12x^3 +3x^2 -5x +3
-12x
------------------
3x^2 -17x +3
-3
-------------
-17x
hmmmm
OpenStudy (anonymous):
thats not correct
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