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Mathematics 16 Online
OpenStudy (anonymous):

solve 6y^2-13y+6=0

OpenStudy (anonymous):

krish will u help

OpenStudy (anonymous):

(;

OpenStudy (anonymous):

x = 3/2 and x = 2/3

OpenStudy (anonymous):

\[6y(y-13) + 6=0\] \[6y +6=0\ or\ y -13 =0 \ so,\ y= -1\ or\ y = 13 \]

OpenStudy (anonymous):

ty

OpenStudy (anonymous):

\[come\ to\ chat\]

OpenStudy (anonymous):

no thanks bye[;

OpenStudy (anonymous):

krish's answer is wrong as i gave earlier y = 3/2 and 2/3

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