Question

How would you put the below system into y= ? form?
x = -(3/2)y
x = (3/2)y - 2

Answer 1

divide each side by -(3/2)
add 2 to each side, then divide each side by (3/2)

Answer 2

so y=x/-(3/2) and y=(x-2)/(3/2)

Answer 3

nono (x+2)/(3/2)

Answer 4

my bad

Answer 5

as they are both = x
-(3/2)y = (3/2)y - 2
divide by -(3/2):
y = -y -2/-(3/2)
2y = 4/3
y = 2/3