The sum of three integers is 47. If the first integer is doubled, the sum is 57. If the second integer is doubled, the sum is 62. Find the integers.
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x+y+z=47 (1) 2x+y+z=57 (2) x+2y+z=62 (3) subtract (1) form (2) x=10 subtract (1) from (3) y=15 plug these into (1) 10+15+z=47 z=22 10,15,22
Good job, but for simplicity, shouldn't you leave out z?
you could do it by saying adding an extra x adds 10 so x=10, adding an extra y adds 15 so y is 15 then find the third. I was trying to turn the statements into equations literally I geuss.
is that what you mean?
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