Help Please! (Attached Picture)

Question

Help Please!  (Attached Picture)

anonymous · Answer

attachment

anonymous · Answer

Thank You In Advance!

anonymous · Answer

Do you know basic trigonometry?

anonymous · Answer

did i not give you a hint that is a right triangle? http://www.oojih.com for more math practice questions and study guide

anonymous · Answer

@lucasmedina,  why would you assume both angles are equal?

anonymous · Answer

I'm sorry I read that wrong I thought those were the segments that were labeled.

anonymous · Answer

oojih.com yes, but i dont know what to do after.  i get 

x^2+30+5x+114=180
x^2+144+5x=180
x^2+5x=36
x(x+5)=36

What next?

anonymous · Answer

<R and <T is not equal

anonymous · Answer

<S=90
<R + <T =90

anonymous · Answer

you are halfway there my friend. x^2+5x-36 =0. You can factor is as (x+9)(x-5)=0

anonymous · Answer

Thank you!!!

anonymous · Answer

@mrbonez, if you want to learn more about solving quadratic equation check: http://www.oojih.com/show/algebra/quadraticfunction/

anonymous · Answer

how much is oojih?

anonymous · Answer

$$x ^{2}+5x+54=90$$$$x ^{2}=5x+54-90=0$$$$x ^{2}+5x-36=0$$$$factor$$$$(x-4)(x+9)=0$$

anonymous · Answer

x=4
or x= -9
 x=4 is solution

anonymous · Answer

@mrbonez, it is free. You can help me by clicking the google ads once in a while.:)

anonymous · Answer

x=5 but when i add everything up i get 194?

anonymous · Answer

I will do that oojih

anonymous · Answer

sorry, it should be x^2+5x-36 =0. You can factor is as (x+9)(x-4)=0

anonymous · Answer

Perfect!  Thank You oojih.com!

anonymous · Answer

can you help me set up part b?