Question

if i basketball player has a leap of 35 inches what is his hangtime?
hang time function v=48t^2

Answer 1

oops

Answer 2

you are solving \[35=48^t\] for t

Answer 3

\[35=48t^2\] for t

Answer 4

divide by 48, take the square root
\[t^2=\frac{35}{48}\]
\[t=\sqrt{\frac{35}{48}}\]

Answer 5

i get about .88