Can someone please help me... If y varies directly as x and inversely as the square of z, and if y= 144 when x=4 and z=3, find y when x=3 and z=4?

Question

owlfred · Answer

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amistre64 · Answer

y = kx/z^2

k = yz^2/x

k = 144(9)/4 = 324

y = 324x/z^2

amistre64 · Answer

y = 324(3)/16 = 60.75  if i see it right

anonymous · Answer

thank you so much!!

amistre64 · Answer

if I was right; youre welcome :)