Question

Can someone please help me... If y varies directly as x and inversely as the square of z, and if y= 144 when x=4 and z=3, find y when x=3 and z=4?

Answer 1

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Answer 2

y = kx/z^2

k = yz^2/x

k = 144(9)/4 = 324

y = 324x/z^2

Answer 3

y = 324(3)/16 = 60.75 if i see it right

Answer 4

thank you so much!!

Answer 5

if I was right; youre welcome :)