Question

can anybody help me please the steps with these (6x+7)(3x+2)

Answer 1

you have to do four multiplications
\[(6x+7)(3x+2)=6x\times 3x+6x\times 2+7\times 3x+7\times 2\]

Answer 2

just mulitply it out

6x +7
3x +2
--------------
12x+14
18x^2 +21x
---------------
18x^2 +33x +14

Answer 3

when you get done you will have
\[18x^2+33x+14\]

Answer 4

you can do it in one line like i did or multiply like you would two "two digit" numbers as amisre did

Answer 5

thanks

Answer 6

i wonder where is the 33 come from?

Answer 7

oh here

Answer 8

\[6x\times 2 + 7\times 3x=12x+21x=33x\]

Answer 9

is the steps suppose to do these
(6x+7)(3x+2)
12x+21x=33x
18x^2+21x
=18x^2+33x+14