Question

watchman can you check this and tell me what you think (i have to attach one sec)

Answer 1

oops i said watchman
i meant watchmath lol

Answer 2

hey watchmath
i assumed e was a good approximate for \[\sum_{i=0}^{2011}\frac{i}{i!}\]

Answer 3

i have to leave but i might be back
feel free to say anything
i will read it :)

Answer 4

oh wait i wait

Answer 5

The integral is divergent

Answer 6

ok i will look at it some more later
and hopefully i can come up with that conclusion

Answer 7

did you look at my attachment?

Answer 8

@myininaya: I think the integral should be from 1 to infinity.

Answer 9

oops you are right lol

Answer 10

The answer is 2011!/(2010)^(2012)

Answer 11

Use this: \(\int_0^{\infty}e^{-t} t^n \, dt =n!\)