myininaya (myininaya):

watchman can you check this and tell me what you think (i have to attach one sec)

6 years ago
myininaya (myininaya):
6 years ago

myininaya (myininaya):

oops i said watchman i meant watchmath lol

6 years ago
myininaya (myininaya):

hey watchmath i assumed e was a good approximate for \[\sum_{i=0}^{2011}\frac{i}{i!}\]

6 years ago
myininaya (myininaya):

i have to leave but i might be back feel free to say anything i will read it :)

6 years ago
myininaya (myininaya):

oh wait i wait

6 years ago
OpenStudy (watchmath):

The integral is divergent

6 years ago
myininaya (myininaya):

ok i will look at it some more later and hopefully i can come up with that conclusion

6 years ago
myininaya (myininaya):

did you look at my attachment?

6 years ago
OpenStudy (watchmath):

@myininaya: I think the integral should be from 1 to infinity.

6 years ago
myininaya (myininaya):

oops you are right lol

6 years ago
OpenStudy (watchmath):

The answer is 2011!/(2010)^(2012)

6 years ago
OpenStudy (watchmath):

Use this: \(\int_0^{\infty}e^{-t} t^n \, dt =n!\)

6 years ago