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Mathematics 23 Online
myininaya (myininaya):

watchman can you check this and tell me what you think (i have to attach one sec)

myininaya (myininaya):

myininaya (myininaya):

oops i said watchman i meant watchmath lol

myininaya (myininaya):

hey watchmath i assumed e was a good approximate for \[\sum_{i=0}^{2011}\frac{i}{i!}\]

myininaya (myininaya):

i have to leave but i might be back feel free to say anything i will read it :)

myininaya (myininaya):

oh wait i wait

OpenStudy (watchmath):

The integral is divergent

myininaya (myininaya):

ok i will look at it some more later and hopefully i can come up with that conclusion

myininaya (myininaya):

did you look at my attachment?

OpenStudy (watchmath):

@myininaya: I think the integral should be from 1 to infinity.

myininaya (myininaya):

oops you are right lol

OpenStudy (watchmath):

The answer is 2011!/(2010)^(2012)

OpenStudy (watchmath):

Use this: \(\int_0^{\infty}e^{-t} t^n \, dt =n!\)

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