OpenStudy (saifoo.khan):

Differentiate: y = (x – 1) (2x – 3)^8

6 years ago
OpenStudy (anonymous):

(x-1) * 8 * (2x-3)^7 * 2 + (2x-3)^8

6 years ago
OpenStudy (saifoo.khan):

anybody with more elaboration?

6 years ago
OpenStudy (saifoo.khan):

thnks bnb

6 years ago
OpenStudy (anonymous):

you dont understand it ?

6 years ago
OpenStudy (angela210793):

[(x – 1) (2x – 3)^8]'=(x-1)' *(2x-3)^8+(x-1)*[(2x-3)^8]'

6 years ago