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y=1-(sin3x-cos3x)^2 equals with y=sin6x (X belongs to R)....but how do u get it? O.o May some1 pls help me?
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essentially both are the same equation.
open the squared term and u'll end up getting 2sin3xcos3x=sin6x
yea i know tht...but how do u transform the 1st into the second?
really?
ok,wait
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I got it!!! Yuupiiii!! :) Thnx :)
1-(sin3x-cos3x)^2=1-(sin^2(3x)+cos^2(3x)-2sin3xcos3x)=1-1+2sin3xcos3x=sin6x . fine ?
Yea thnx :)
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