ok i found the tangent line which is y=5x-19...now i need to find f(6) and F'(6)..can someone help me please?...o and tha tangent line at (6,3) passes through the point (0,2)....

Question

anonymous · Answer

i don't understand wat question ur asking...if u hav the actual ques, just copy paste it...i'll help u out :)

anonymous · Answer

ok here it is.....Find an equation of the tangent line to the graph of y = g(x) at x = 3 if g(3) = −4 and g'(3) = 5. which i got it to be y=5x-19 
If the tangent line to y = f (x) at (6, 3) passes through the point (0, 2), find f(6) and f '(6).

anonymous · Answer

ok, for this u don't need any information from g(x) or g'(x)

f'(6) is the slope of the line joining (0,2) and (6,3) , which is 1/6;
now find the equation of this tangent line, and f(6) is the y value in the tangent equation . 
got it huh?

anonymous · Answer

yea so the reverse would be 6 right?

anonymous · Answer

so that would be $$y=5(6)-19?$$