Question

Suppose that sec(B) = - 8⁄3 and that 180o < B < 270o. Find sin(B).

Answer 1

cos B=-3/8
sin b=sqrt(1-(cos x)^2)
sin b=sqrt(1-9/64)
sin b=sqrt(55/64)
since sin is negative in thord quadrant so sin b=-sqrt(55)/8.

Answer 2

great!