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A bag contains a total of 8 batteries, of which three are defective. Selecting three at random, without replacement, determine the probability that none of the batteries you select are good.
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if ur drawing the batteries at the same time , then the probability is 3/8 but wen ur drawing batteries one by one then, the probability is (3/8)*(2/7)8(1/6)
gramiof2:got it?
i think the 8 is a typo yes?
\[\frac{3}{8}\times \frac{2}{7}\times \frac{1}{6}\]
I think it is 1/56
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yea the 8 there was *---missed the shift key :)
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