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Mathematics 11 Online
OpenStudy (anonymous):

78. During lunch at Urbana Middle School today, several students have brought their lunch from home and several students are ordering a school lunch as shown in the table. Suppose one student is randomly selected during lunch time. What is the probability that the student orders school lunch? Brought lunch from home 55 Order school lunch 45 6th graders 32 7th graders 35 8th graders 33

OpenStudy (anonymous):

45/100

OpenStudy (anonymous):

is the number of students in 6th ,7th and 8th included in the experiment ?

OpenStudy (anonymous):

yes they are included

OpenStudy (anonymous):

further reduced to 9/20

OpenStudy (anonymous):

then the probability is 45/185

OpenStudy (anonymous):

how did you get the answer

OpenStudy (anonymous):

oops! sorry calculation mistake:total number of peopl in the experiment is 55+45+32+35+33=200 and hence it is 45/200

OpenStudy (anonymous):

brackett, the question means to say of the 6th 7th and 8th graders, 45 order school lunch and 55 bring their own. So it's 45/100

OpenStudy (anonymous):

the total students are 100 -- 55 + 45 then the breakup of 100 per standard is given (their total is also 100) this breakup is of no use here

OpenStudy (anonymous):

@lucas:yea thats makes sense though :)

OpenStudy (anonymous):

the way the question is written is confusing.

OpenStudy (anonymous):

i didnt write it my teacher did

OpenStudy (anonymous):

Hey 3077097a, pls click my GOOD ANSWER button :))

OpenStudy (anonymous):

the number of students in each grade is superfluous! Perhaps its there to confuse!! lol

OpenStudy (anonymous):

maybe i dont know

OpenStudy (anonymous):

thanks anyways

OpenStudy (anonymous):

45/100 chance is the same as 45% chance so you can just say that.

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