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whats the volume of the solid obtained when rotating the region under the graph of the function f(x)= x^(13/12)?? on the interval [1,3]??? need help
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creeg go back to your previous request to get the solution
how do i do that
vol = INT pi f(x)^2 dx between x = 1 and 3 = INT pi x^169/144 dx = pi [x^313/144 * 144/313] btw 1 and 3 = = pi [3^313/144 * 144/313 -1^313/144 * 144/313 ]
aww its all squashed up - i copied it but its come out like that
just scroll down on the left to findn ur previous post
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rotated about which axis?
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