Question

need help on a math work sheet these question are difficult please show work

Answer 1

where are the problems/

Answer 2

ah! marxin is back !

Answer 3

did u expect me to stay away from this awesome site????

Answer 4

nice worksheet!

Answer 5

what is this from 1962?

Answer 6

any specific problem?

Answer 7

all of them startin with one i got to get these right

Answer 8

Your last problem is wrong. It should be d. You foil the whole thing, then you add like terms. First Outer Inner Last

Answer 9

and srry if i take a while cpu movin slow today

Answer 10

first one is right
second one is right
third one is wrong. if you multiply out your selection you will see that you do not get 11x as the 'middle term"

Answer 11

you would get 2x - 6x = -4x but you want 11x. i think a) will give it to you

Answer 12

ok that seems right

Answer 13

fourth one is wrong.
\[(2t^2-t-28)\div (t-4)\] you are trying to solve
\[2t^2-t-25=(t-4)(something)\]

Answer 14

As soon as someone sees "difficult" on this website everyone flocks xDDD Whats up marxin?

Answer 15

nuthin braw jus back with hm last day too get it done n yall r a big help

Answer 16

that something has to look like \[(2t \pm b)\] because otherwise you will not get
\[2t^2\] as your first term

Answer 17

pick
\[(2t+7)\] because
\[2t\times t = 2t^2\] and
\[-4\times 7 = -28\]

Answer 18

I feel that. I hope it turns out good for you xP

Answer 19

and unfortunately the fifth one is wrong because the expansion fo
\[(a+b)^4=a^4+4a^3b+6a^2b^2+4ab^3+b^4\]

Answer 20

so your coefficients should look like
1 4 6 4 1, not

1 5 10 5 1

Answer 21

so its d right

Answer 22

no

Answer 23

coefficients should be 1 4 6 4 1

Answer 24

so then it's between a n b i go with a

Answer 25

Its A. And it can't be the one with 1 5 10 5 1. Because those aren't correct. They would read: 1 5 10 10 5 1 :P And since it is (a-b)^4. You have alternating minus signs. So A.

Answer 26

ok i get it we have to use coherants ok rady for the next work sheet