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6=x^3+4x
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cubed?
yes
have fun. \[x^3+4x-6=0\] and now i am stuck. it must have one real zero, and i guess we could try to get a decimal approximation using newton's method. there is a formula but a) i don't know it and b) it is a real pain
use maple, wolfram, graphing calculator, some machine
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thanks
not much help but you are welcome
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