Question

-8(x-3)>-11x+8 solution using set builder notation

Answer 1

rsvitale! hey

Answer 2

hello :)

Answer 3

do you want to answer this one or should I?

Answer 4

you go ahead i will find another

Answer 5

i posted the sol. to that integral

Answer 6

i seen

Answer 7

k

Answer 8

susie:
divide both sides by -8, and since we divide by a negative we flip the inequality:

x-3< (11/8)x-1
subtract x from both sides and add one to both sides:
-2<(3/8)x
multiply by 8/3
-16/3<x

now in set builder notation the solution S is:

S={x|x>-16/3}

read S is the set of all x such that x is greater than -16/3

Answer 9

thanks that helps