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OpenStudy (anonymous):
How do you solve 10a+10>9a+22 Then reprsent answer in set builder notation. show work. Thanks
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OpenStudy (anonymous):
becca!!! so yea, a>12 is what u get. so u write a={x|x>12 and x belongs-to(symbol) r}
OpenStudy (anonymous):
Can you show me how you got a>12
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