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Where on the curve x^2 - 2xy + y^3 = 1 is the slope of the curve vertical?
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Take a derivative. Find where it is undefined.
2x -2 (x dy/dx +y ) +3y^2 dy/dx = 0 2x -2x dy/dx -2y +3y^2 dy/dx =0
\[\frac{dy}{dx} = \frac{2y-2x}{3y^2-2x}\]
if you set the denominator equal to zero you will get a sideways parabola
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