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Solve each system of equations by substitution : y = –2x – 5 y = 3x + 20
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u need to get the value of x and y ?
yes, please
x=-5 and y=5
Solve each system of equations by substitution. y = 2x – 11 y = –3x + 14
3x + 20 +2x+5 = 0 5x = -25 x = -5 y = 3*(-5) +20 = 5
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x = 5 , y = -1
from the first equation , substistute for y in the second. 3x+20 -2x-5 3x + 20 +2x+5 = 0 5x = -25 x = -5 y = 3*(-5) +20 = 5
2 moar?
oki
its diff tho. 1 sec
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Simplify the rational expression: (x^2+4x-5)/(x^2-4x+3)
factorise both the numerator and denominator...and cancel out the common factors.... u get (x+5)/(x-3)
u sure the denominator u wrote is right ?
oh nm
1 mor
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Simplify the rational expression: (m+2)/(m^2-3m-10)
1/(m-5)
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